基于layui table返回的值的多级嵌套的解决方法

data = res[options.response.dataName] || []

function searchData(response,res,name){
var data = new Object();
var arr = response[name].split("/"),
pre = arr[0];
data[pre] = res[pre];
for(var i = 1;i<arr.length;i++){
if(arr[i]){
var next = arr[i];
data[pre] = data[pre][next];
}
}

try{
countNameInfo = response.countName;
dataNameInfo = response.dataName;
//console.log(options.response)
res.newcountName = searchData(response,res,“countName”);
res.newdataName = searchData(response,res,“dataName”);
}catch(err){
console.log(err.message);
}

response.countName = countNameInfo;
response.dataName = dataNameInfo;

countName: ‘你多级嵌套的节点值' //数据总数的字段名称，默认：count
,dataName: ‘你多级嵌套的节点值' //数据列表的字段名称，默认：data