基于Python的身份证号码自动生成程序

def getdistrictcode():
  with open('districtcode') as file:
    data = file.read()
  districtlist = data.split('\n')
  global codelist
  codelist = []
  for node in districtlist:
    #print node
    if node[10:11] != ' ':
      state = node[10:].strip()
    if node[10:11]==' 'and node[12:13]!=' ':
      city = node[12:].strip()
    if node[10:11] == ' 'and node[12:13]==' ':
      district = node[14:].strip()
      code = node[0:6]
      codelist.append({"state":state,"city":city,"district":district,"code":code})

def gennerator():
  id = codelist[random.randint(0,len(codelist))]['code'] #地区项
  id = id + str(random.randint(1930,2013)) #年份项
  da = date.today()+timedelta(days=random.randint(1,366)) #月份和日期项
  id = id + da.strftime('%m%d')
  id = id+ str(random.randint(100,300))#，顺序号简单处理

  i = 0
  count = 0
  weight = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2] #权重项
  checkcode ={'0':'1','1':'0','2':'X','3':'9','4':'8','5':'7','6':'6','7':'5','8':'5','9':'3','10':'2'} #校验码映射
  for i in range(0,len(id)):
    count = count +int(id[i])*weight[i]
  id = id + checkcode[str(count%11)] #算出校验码
  return id