一个计算身份证号码校验位的Python小程序

import sys

Wi = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7,9, 10, 5, 8, 4, 2]
IndexTable = { #此处实际是无需使用字典的，使用一个包含11个元素的数组便可，数组中存放
        0 : '1', #相应位置的号码，但是这也正好演示了Python高级数据结构的使用
        1 : '0',
        2 : 'x',
        3 : '9',
        4 : '8',
        5 : '7',
        6 : '6',
        7 : '5',
        8 : '4',
        9 : '3',
        10 : '2'
    }
No = []
sum = 0
if (len(sys.argv[1:][0]) != 17):
    print "error number"
    sys.exit()
for x in sys.argv[1:][0]:
        No.append(x)
for i in range(17):
    sum = sum + (int(No[i]) * Wi[i])
Index = sum % 11
print "So, your indicates parity is : %s" % (IndexTable[Index])

import sys

if __name__ != '__main__':
  print "Cannot run in module"
  sys.exit()

Wi = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7,9, 10, 5, 8, 4, 2]
IndexTable = {
    0 : '1',
    1 : '0',
    2 : 'x',
    3 : '9',
    4 : '8',
    5 : '7',
    6 : '6',
    7 : '5',
    8 : '4',
    9 : '3',
    10 : '2'
  }

def check(identity):
  if(len(identity) == 0):
    print "please input your identity number"
    sys.exit()
  elif (len(identity[0]) != 17):
    print "error number"
    sys.exit()

def calculate(identity):
  No = []
  sum = 0
  for x in identity[0]: #这个方法是很笨拙的，直接使用No = list(identity[0])便可达到同样的目的
    No.append(x)

  for i in range(17):
    sum = sum + (int(No[i]) * Wi[i])

  Index = sum % 11
  return IndexTable[Index]

check(sys.argv[1:])
result = calculate(sys.argv[1:]) 

print "So, your indicates parity is : %s" % (result)