Python cookbook（数据结构与算法）字典相关计算问题示例

> prices = {
 'ACME': 45.23,
 'AAPL': 612.78,
 'IBM': 205.55,
 'HPQ': 37.20,
 'FB': 10.75
}
> prices
{'HPQ': 37.2, 'IBM': 205.55, 'FB': 10.75, 'ACME': 45.23, 'AAPL': 612.78}
> min_price = min(zip(prices.values(), prices.keys())) #注意zip(x,y)中参数的顺序
> max_price = max(zip(prices.values(), prices.keys()))
> min_price
(10.75, 'FB')
> max_price
(612.78, 'AAPL')
> prices_sorted = sorted(zip(prices.values(), prices.keys()))
> prices_sorted
[(10.75, 'FB'), (37.2, 'HPQ'), (45.23, 'ACME'), (205.55, 'IBM'), (612.78, 'AAPL')]
> min_price2 = min(zip(prices)) #错误用法
> min_price2
('AAPL',)
> max_price2 = max(zip(prices)) #错误用法
> max_price2
('IBM',)
> min_price3 = min(zip(prices.keys(), prices.values())) #zip()参数顺序不对，获取错误的值
> min_price3
('AAPL', 612.78)
> max_price3 = max(zip(prices.keys(), prices.values())) #zip()参数顺序不对，获取错误的值
> max_price3
('IBM', 205.55)
>

> pirces_and_names=zip(prices.values(), prices.keys())
> pirces_and_names
<zip object at 0x023BDFA8>
> min(pirces_and_names)
(10.75, 'FB')
> max(pirces_and_names)
Traceback (most recent call last):
 File "<pyshell#25>", line 1, in <module>
 max(pirces_and_names)
ValueError: max() arg is an empty sequence
>

> prices={'AAA':45.23,'ZZZ':45.23}
> min(zip(prices.values(), prices.keys()))
(45.23, 'AAA')
> max(zip(prices.values(), prices.keys()))
(45.23, 'ZZZ')
>