Python使用zip合并相邻列表项的方法示例

> x
[1, 2, 3, 4, 5, 6, 7, 8, 9]
> zip(*[iter(x)]*2)
[(1, 2), (3, 4), (5, 6), (7, 8)]
> zip(*[iter(x)]*3)
[(1, 2, 3), (4, 5, 6), (7, 8, 9)]
> zip(*[iter(x)]*4)
[(1, 2, 3, 4), (5, 6, 7, 8)]

> [iter(x)]*3
[<listiterator object at 0x02F4D790>, <listiterator object at0x02F4D790>, <listiterator object at 0x02F4D790>]

> x
[1, 2, 3, 4, 5, 6, 7, 8, 9]
> group_adjacent = lambda a, k: zip(*([iter(a)] * k))
> group_adjacent(x,3)
[(1, 2, 3), (4, 5, 6), (7, 8, 9)]
> group_adjacent(x,2)
[(1, 2), (3, 4), (5, 6), (7, 8)]
> group_adjacent(x,1)
[(1,), (2,), (3,), (4,), (5,), (6,), (7,), (8,), (9,)]

> x
[1, 2, 3, 4, 5, 6, 7, 8, 9]
> zip(x[::2],x[1::2])
[(1, 2), (3, 4), (5, 6), (7, 8)]
> zip(x[0::2],x[1::2])
[(1, 2), (3, 4), (5, 6), (7, 8)]
> zip(x[0::3],x[1::3],x[2::3])
[(1, 2, 3), (4, 5, 6), (7, 8, 9)]
> zip(x[::3],x[1::3],x[2::3])
[(1, 2, 3), (4, 5, 6), (7, 8, 9)]

> x
[1, 2, 3, 4, 5, 6, 7, 8, 9]
> group_adjacent = lambda a, k: zip(*[a[i::k] for i in range(k)])
> group_adjacent(x,3)
[(1, 2, 3), (4, 5, 6), (7, 8, 9)]
> group_adjacent(x,2)
[(1, 2), (3, 4), (5, 6), (7, 8)]
> group_adjacent(x,1)
[(1,), (2,), (3,), (4,), (5,), (6,), (7,), (8,), (9,)]