Python利用公共键如何对字典列表进行排序详解

l = [{'x':1, 'y':2}, {'x':2, 'y':3}, {'x':3, 'y':4}]

> l = [{'x':1, 'y':2}, {'x':2, 'y':3}, {'x':3, 'y':4}]
> l1 = sorted(l, key=lambda d:d['x'], reverse=True)
> l1
[{'y': 4, 'x': 3}, {'y': 3, 'x': 2}, {'y': 2, 'x': 1}]
>

> from operator import itemgetter
> l = [{'x':1, 'y':2}, {'x':2, 'y':3}, {'x':3, 'y':4}]
> l2 = sorted(l, key=itemgetter('x'), reverse=True)
> l2
[{'y': 4, 'x': 3}, {'y': 3, 'x': 2}, {'y': 2, 'x': 1}]
>

l_by_x = sorted(l, key=lambda d:d['x'])
l_by_xy = sorted(l, key=lambda d:(d['x'], d['y']))

l_by_x = sorted(l, key=itemgetter('x'))
l_by_xy = sorted(l, key=itemgetter('x', 'y'))

> min(l, key=itemgetter('x'))
{'y': 2, 'x': 1}
> max(l, key=itemgetter('x', 'y'))
{'y': 4, 'x': 3}
> max(l, key=itemgetter('x'))
{'y': 4, 'x': 3}
>