PHP实现发送和接收JSON请求

$url = "http://example.com/request/post/json"; 
$data = json_encode(["foo" => "bar"]);
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER, array("Content-type: application/json"));
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
curl_exec($curl);
curl_close($curl);

$data = json_decode(file_get_contents('php://input'), true);

//Guzzle version >= 5
use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
 GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar']
]);

//IN controller
public function recieveJson(Request $request)
{
 $request->json()->all();
 //返回值是一个数组
 //针对前面的请求例子，json方法返回的是数组 ["foo" => "bar"]
 //$request->json()返回的是ParamBage
}

public function laravelRecieveJson(Reuqest $request)
{
  $foo = $request->input('foo');//echo $foo => 'bar'
  //使用点号获取内嵌数组key的值
  //假设请求体中的JSON为 {"user": {"name": "kevin", "age": 18}}
  $name = $reqeust->input('user.name');//echo $name => 'kevin'
}