python 获取url中的参数列表实例

import urlparse
urldata = "http://en.wikipedia.org/w/api.php"
result = urlparse.urlparse(urldata)
print result
print urlparse.parse_qs(result.query)

ParseResult(scheme='http', netloc='en.wikipedia.org', path='/w/api.php', params='', query='action=query&ctitle=FA', fragment='')
{'action': ['query'], 'ctitle': ['FA']}