python创建属于自己的单词词库 便于背单词

import requests
from bs4 import BeautifulSoup
import re
import traceback
import sqlite3
import time
import sys

def ycl(word):
 try:
 url = "http://www.iciba.com/{}".format(word)
 headers = { 'Host': 'www.iciba.com', 'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:43.0) Gecko/20100101 Firefox/43.0', 'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'Accept-Language': 'zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3', 'Accept-Encoding': 'gzip, deflate', 'Referer': 'http://www.baidu.com', 'Connection': 'keep-alive', 'Cache-Control': 'max-age=0', }
 response = requests.get(url = url,headers = headers)
 soup = BeautifulSoup(response.text,"lxml")
 #输出单词词性
 cx = soup.find(class_='base-list switch_part')(class_='prop')
 #输出词性词义
 mp3 = soup.find_all(class_='new-speak-step')[1]
 pattern = re.compile(r'http://("E:\\sound\\"
 mp3path = dress +word+".mp3"
 with open(mp3path, 'wb') as f:
  f.write(r.content)
 #获取词性个数
 meanings =soup.find_all(class_='prop')
 #实行每个词性的词义同行输出
 for i in range(len(meanings)):
  s = soup.find(class_='base-list switch_part')('li')[i]('span')
  c = cx[i].text
  a = ''
  for x in range(len(s)):
  b = s[x].text
  a = a + b
  print(word)
  print(c)
  print(a)
  # 存入数据库的方法
  conn = sqlite3.connect("word.db")
  cu = conn.cursor() 
  sql =cu.execute("INSERT INTO test (id,dc,cx,cy,mp3)VALUES(NULL,'%s','%s','%s','%s');"%(word,c,a,mp3path))
  print(sql)
  conn.commit()
  print('\n')
 except Exception as e:
 print(e)
 print("error")
 with open("log.txt",'a') as f:
  f.write(word+'\n')
def duqudanci(file):
 wordcount = 0
 for line in open(file):
 word = line.strip('\n')
 wordcount += 1
 print(wordcount)
 ycl(word)
 
if __name__ == '__main__':
 conn = sqlite3.connect("word.db")
 cu = conn.cursor()
 word = ""
 #需要爬取的单词
 duqudanci(sys.argv[1])
 print('下载完成')
 conn.commit()
 conn.close()

import sqlite3
import random
import sys
from playsound import playsound 
# 中译英
def CtoE():
 for j in list1:

 sql =cu.execute('select id,dc,cx,cy,mp3 from wordinfo where id = "当前单词ID = "+str(it[0]))
 print("释义："+it[3])
 # 播放音频
 playsound(it[4])
 a = input("请拼写单词,共有三次机会:")
 if a == it[1]:
 print("拼写正确")
 break;
 c += 1
 print('第%d次拼写错误'%c)
 print('\n')
 print("下一个")
 print('\n')
# 英译中
def EtoC():
 for j in list1:
 sql =cu.execute('select id,dc,cx,cy,mp3 from wordinfo where id = "当前单词ID = "+str(it[0]))
 print("选择单词的对应释义：----"+it[1])
 playsound(it[4])
 dict1 = {'A':list2[0],'B':list2[1],'C':list2[2],'D':list2[3]}
 print("A:"+dict1.get('A')+'\n')
 print("B:"+dict1.get('B')+'\n')
 print("C:"+dict1.get('C')+'\n')
 print("D:"+dict1.get('D')+'\n')
 answer1 = input("请选择，共有三次机会(大写)：")
 if dict1.get(answer1)== it[3]:
 print("正确")
 break;
 c += 1
 print('第%d次拼写错误'%c)
 d += 1
 print('\n')
 print("下一个")
 print('\n')
def main(file):
 for line in open(file):
 word = line.strip('\n')
 sql =cu.execute('select id from wordinfo where dc = "英译中请选1，中译英请选2:")
 if cho =="1":
 EtoC() 
 elif cho =="2":
 CtoE()
 else:
 print("错误，请重试")

if __name__ == '__main__':
 conn = sqlite3.connect("word.db")
 cu = conn.cursor() 
 list1 = []
 word = ""
 main(sys.argv[1])
 conn.commit()
 conn.close()