Python编程学习之如何判断3个数的大小

a = int(input('a>'))
b = int(input('b>'))
c = int(input('c>'))
if a>b:
 if b>c:
 print('a>b>c')
 else:
 if a>c:
  print('a>c>b')
 else:
  print('c>a>b')
elif a<b:
 if b<c:
 print('c>b>a')
 else:
 if c>a:
  print('b>c>a')
 else:
  print('b>a>c')

nums = []
for i in range(3):
 nums.append(int(input('{}; '.format(i))))
if nums[0]>nums[1]:
 if nums[0]>nums[2]:
  i3 = nums[0]
  if nums[1] > nums[2]:
  i2 = nums[1]
  i1 = nums[0]
  else:
  i2 = nums[0]
  i1 = nums[1]
 else:#0<2 1<0
  i3 = nums[2]
  i2 = nums[0]
  i1 = nums[1]
else: #[0]<[1]
 if nums[0] < nums[2]:
 i1 = nums[0]
 if nums[1] < nums[2]:
  i2 = nums[1]
  i3 = nums[2]
 else:#[1]>[2]
  if nums[0] > nums[2]:
  i2 = nums[0]
  i3 = mums[2]
  else:
  i2 = nums[2]
  i3 = mums[0]
print(i1,i2,i3)

nums = []
for i in range(3):
 nums.append(int(input('{}: '.format(i))))
#此处不能使用for循环，不能一边迭代该列表，同时删除或者增加该列表
while True:
 x = max(nums)
 print(x)
 nums.remove(x)
 if len(nums) == 1:
 print(nums[0])
 break

nums = []
out = None
for i in range(3):
 nums.append(int(input('{}: '.format(i))))
nums.sort()
print(nums)