Python *args和**kwargs用法实例解析

def fun(*arg):
  print(arg,type(arg))
  print(*arg)
fun(1,2,[8,9])
(1, 2, [8, 9]) <class 'tuple'>
2 [8, 9]

print(kwarg,type(kwarg))
  # print(**kwarg)#TypeError: 'a' is an invalid keyword argument for print()

fun(a=1,b=6)
fun(**{'name':'Peter','gender':'male'})
{'a': 1, 'b': 6} <class 'dict'>
{'name': 'Peter', 'gender': 'male'} <class 'dict'>

def fun(*args,**kwarg):
  print(args,kwarg,type(kwarg))
  # print(**kwarg)#TypeError: 'a' is an invalid keyword argument for print()
fun(a=6,1,2,3,**{'name':'Peter','gender':'male'})

File "C:/Users/Administrator.SC-201903160419/Desktop/笔记/myrequest.py", line 37
  fun(a=6,1,2,3,**{'name':'Peter','gender':'male'})
      ^
SyntaxError: positional argument follows keyword argument