python中函数返回多个结果的实例方法

$ vim e3.py
def damage(skill1,skill2):
  damage1 = skill1 * 3
  damage2 = skill2 * 2 + 10
  return damage1,damage2
skill1_damage,skill2_damage = damage(3,6) 
print(skill1_damage,skill2_damage)

import math
def move(x, y, step, angle=0):
  nx = x + step * math.cos(angle)
  ny = y - step * math.sin(angle)
  return nx, ny

> x, y = move(100, 100, 60, math.pi / 6)
> print(x, y)
151.96152422706632 70.0

> r = move(100, 100, 60, math.pi / 6)
> print(r)
(151.96152422706632, 70.0)