Python实例教程之检索输出月份日历表

def day(y, m, d):#计算y年m月d日是星期几

 y0 = y - (14 - m)//12
 x = y0 + y0//4 - y0//100 + y0 //400
 m0 = m + 12*((14 - m)//12) - 2
 d0 = (d + x + 31*m0//12) % 7
 return d0 #注意，周日是0

def isLeapYear(year): #判断year年是否闰年
 isLeapYear = True 
 if year % 4 ==0: #整除可不是等于0，天
 if year % 100 ==0:
 if year % 400 ==0:
 isLeapYear = True
 else:
 isLeapYear = False
 else:
 isLeapYear = True 
 else:
 isLeapYear = False #注意是一个等号还是两个等号
 return isLeapYear

def calendar(y, m): #打印y年m月日历
 print(' {}年{}月'.format(y,m))
 print('Su\tM\tTu\tW\tTh\tF\tSa')
 # 请在下面编写代码
 # ********** Begin ********** #
 month_1 = [1,3,5,7,8,10,12]
 month_2 = [4,6,9,11]
 momth_number = 0
 if isLeapYear(y): #计算这个月有多少天
 if m == 2:
 month_number = 29
 else:
 if m in month_1:
 month_number = 31
 if m in month_2:
 month_number = 30
 else:
 if m == 2:
 month_number = 28
 else:
 if m in month_1:
 month_number = 31
 if m in month_2:
 month_number = 30 
 
 table = day(y, m, 1) #空格 排列输出
 for j in range (1,month_number + 1): #注意加一
 if j == 1:
 print("\t" * table,end = '')
 j = str(j)
 print(j + "\t",end = '')
 j = eval(j)
 if (j + day(y, m, 1)) % 7 == 0:
 print("\r")
 print("\r")
 
for (y,m) in [(2020,12), (2017,2), (2016,2)]:
 calendar(y, m)
 print('---------------------------')

def day(y, m, d):
 y0 = y - (14 - m)//12
 x = y0 + y0//4 - y0//100 + y0 //400
 m0 = m + 12*((14 - m)//12) - 2
 d0 = (d + x + 31*m0//12) % 7
 return d0 

def isLeapYear(year): #判断year年是否闰年
 isLeapYear = True 
 if year % 4 ==0: #整除可不是等于0，天
 if year % 100 ==0:
  if year % 400 ==0:
  isLeapYear = True
  else:
  isLeapYear = False
 else:
  isLeapYear = True 
 else:
 isLeapYear = False #注意是一个等号还是两个等号
 return isLeapYear

 table = day(y, m, 1) #求空格数
 for j in range (1,month_number + 1): #注意加一
 if j == 1:
  print("\t" * table,end = '')
 j = str(j)
 print(j + "\t",end = '')
 j = eval(j)
 if (j + day(y, m, 1)) % 7 == 0:
  print("\r")
 print("\r")