详解Django关于StreamingHttpResponse与FileResponse文件下载的最优方法

def streamDownload(resquest):
 def file_iterator(filepath, chunk_size = 512):
 with open(filepath, 'rb') as f:
  while True:
  con = f.read(512)
  if con:
   yield con
  else:
   break
 filename = os.path.abspath(__file__) + 'test.txt'
 response = StreamingHttpResponse(file_iterator(filename)
 return response 
# 最后程序会将结果打印在显示器上

def homeproc2(request):
 cwd = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
 response = FileResponse(open(cwd + "/msgapp/templates/youfile", "rb"))
 response['Content-Type] = 'application/octet-stream'
 response['Content-Disposition'] = 'attachment;filename="filename"'
 return response

 response['Content-Type] = 'application/octet-stream'
 response['COntent-Disposition'] = 'attachment;filename="filename"'