python爬虫实现爬取同一个网站的多页数据的实例讲解

def get_page_size(soup):
  pcxt=soup.find('div',{'class':'babynames-term-articles'}).find('nav')
  pcxt1=pcxt.find('div',{'class':'nav-links'}).findAll('a')
  for i in pcxt1[:-1]:
    link=i.get('href')
    s=str(i)
  page=re.sub('<a href="','',s)
  page1=re.sub(link,'',page)
  page2=re.sub('">','',page1)
  page3=re.sub('</a>','',page2)
  pagesize=int(page3)
  print(pagesize)
  return pagesize
Pass

if __name__ == '__main__':
    url="http://www.sheknows.com/baby-names/browse/a/"
    soup=get_requests(url)
    page=get_page_size(soup)
    for i in range(1,page+1):
      url1=url+"page/"+str(i)+"/"
      soup1=get_requests(url1)
      draw_base_list(soup1)

import requests
from lxml import etree
import re

url="https://movie.douban.com/top250"
header = {"User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/79.0.3945.130 Safari/537.36"}

allMovieList=[]
flag = True
while flag:
  html = requests.get(url, headers=header).text
  list = etree.HTML(html)
  lis = list.xpath('//ol[@class="grid_view"]/li')
  for oneSelector in lis:
    name = oneSelector.xpath("div/div[2]/div[1]/a/span[1]/text()")[0]
    score = oneSelector.xpath("div/div[2]/div[2]/div/span[2]/text()")[0]
    people = oneSelector.xpath("div/div[2]/div[2]/div/span[4]/text()")[0]
    people = re.findall("(.*",people)[0]
    oneMovieList = [name,score,people]
    allMovieList.append(oneMovieList)
  #获取下一页地址
  try:
    next_url = list.xpath('//span[@class="next"]/a/@href')[0]
    if next_url:
      url = "https://movie.douban.com/top250"+ next_url
  except:
    flag = False
print(allMovieList)