JS实现简单的二元方程计算器功能示例

网络编程 2024/11/13 佚名

3 2 1

本文实例讲述了JS实现简单的二元方程计算器功能。分享给大家供大家参考，具体如下：

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML>
<HEAD>
<TITLE>二元方程</TITLE>
<META NAME="Author" CONTENT="">
<META NAME="Keywords" CONTENT="">
<META NAME="Description" CONTENT="">
</HEAD>
<BODY>
<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
var rootparti;
var rootpart;
var det;
var rootparti1;
var rootparti2;
var a;
var b;
var c;
var x1;
var x2;
var i = "i";
function checkQuad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
if (a == 0 && c != 0) {
x1 = -c / b;
x2 = "Not a quadratic equation, but here is your answer for x";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else if (a == "" && c != 0) {
x1 = -c / b;
x2 = "Not a quadratic equation";
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
else {
quad();
  }
}
function quad() {
var a = document.fquad.fa.value;
var b = document.fquad.fb.value;
var c = document.fquad.fc.value;
det = Math.pow(b,2) - 4 * a * c;
rootpart = Math.sqrt(det) / (2 * a);
rootparti = (Math.sqrt(-det) / (2 * a)) + i;
if (parseFloat(rootparti) < 0) {
rootparti1 = rootparti;
rootparti2 = (-1 * parseFloat(rootparti)) + i;
}
else {
rootparti1 = (-1 * parseFloat(rootparti)) + i;
rootparti2 = rootparti;
}
if (rootparti1 == "1i") {
rootparti1 = i;
rootparti2 = "-i";
}
else if (rootparti1 == "-1i") {
rootparti1 = "-i";
rootparti2 = i;
}
if (det == 0) {
x1 = x2 = -b / (2 * a);
}
else if (det > 0) {
x1 = (-b + Math.sqrt(det)) / (2 * a);
x2 = (-b - Math.sqrt(det)) / (2 * a);
}
else if ((-b / (2 * a)) == 0) {
x1 = rootparti1;
x2 = rootparti2;
}
else {
x1 = (-b / (2 * a) + " + " + rootparti1);
x2 = (-b / (2 * a) + " + " + rootparti2);
}
document.fquad.x1.value=x1;
document.fquad.x2.value=x2;
}
// End -->
</script>
<form name=fquad>
 <table align="center">
  <tr>
<td>
<h2>
<input name=fa size=4>
 <font color="#33FF33">x<SUP>2</SUP>+</font> 
 <input name=fb size=4>
 <font color="#33FF33"> x +</font> 
 <input name=fc size=4>
 <font color="#33FF33">= 0</font> 
 <input type=button value="求值" onClick="checkQuad()">
 <input type=reset value="重填">
</h2>
</td>
</tr>
<tr>
<td>
<h2> <font color="#33FF33">x<sub>1</sub>=</font>
<input name=x1 size=45>
 <font color="#33FF33">x<sub>2</sub>= </font>
<input name=x2 size=45>
</h2>
</td>
</tr>
</table>
</form>
</BODY>
</HTML>

PS：这里再为大家推荐几款计算工具供大家进一步参考借鉴：

在线一元函数（方程）求解计算工具：
http://tools.jb51.net/jisuanqi/equ_jisuanqi

科学计算器在线使用_高级计算器在线计算：
http://tools.jb51.net/jisuanqi/jsqkexue

在线计算器_标准计算器：
http://tools.jb51.net/jisuanqi/jsq

更多关于JavaScript相关内容感兴趣的读者可查看本站专题：《JavaScript数学运算用法总结》、《JavaScript数据结构与算法技巧总结》、《JavaScript数组操作技巧总结》、《JavaScript排序算法总结》、《JavaScript遍历算法与技巧总结》、《JavaScript查找算法技巧总结》及《JavaScript错误与调试技巧总结》

希望本文所述对大家JavaScript程序设计有所帮助。

JS,二元方程,计算器