Python实现打印螺旋矩阵功能的方法

#coding:utf-8
n = int(raw_input('>'))
#初始化数组
arr = [[0]*n for i in range(n)]
#递归解决
def dfs(arr, x, y, start, n):
  if n<=0:return 0
  if n==1:
    arr[x][y] = start
    return 0
  #up
  for i in range(n):
    arr[x][y+i] = start
    start += 1
  #right
  for i in range(n-1):
    arr[x+1+i][y+n-1] = start
    start += 1
  #down
  for i in range(n-1):
    arr[x+n-1][y+n-2-i] = start
    start += 1
  #left
  for i in range(n-2):
    arr[x+n-2-i][y] = start
    start += 1
  dfs(arr,x+1,y+1,start,n-2)
a = dfs(arr,0,0,1,n)
#格式化输出print
l = len(str(n*n))+1
format = ('%'+str(l)+'d')*n
for tmp in arr:
  print format%tuple(tmp)